6" / 8" squares set on point question
10-13-2011, 03:53 AM
#1
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Everyone here seems to know where to locate information or can offer the answers to questions soooooooooo'
My question is if you set squares on point how would you figure the finished width, I am trying to adjust a pattern to fit the measurements I need and do not know how I should figure for setting them on point.....TIA
My question is if you set squares on point how would you figure the finished width, I am trying to adjust a pattern to fit the measurements I need and do not know how I should figure for setting them on point.....TIA
10-13-2011, 04:03 AM
#3
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Originally Posted by Darlene
I woul;d use 6 1/2 or 8 1/2 squares.
10-13-2011, 04:04 AM
#4
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You multiply the FINISHED size of the block by 1.414 to get the FINISHED width of the block when on point.
An 8" FINISHED block on point will be ~11.3" across (the measurement of the FINISHED diagonal).
If you have created a design where you want six on-point blocks/squares that are ~10" across (because you want a 60" wide top), you would reverse the formula:
10" divided by 1.414 = 7.07" (and round up or down),
THEN add the seam allowance to cut the squares.
For blocks, I'd want them to be the 7" (or 7.125" or 7.25", depending on how you round) FINISHED.
An 8" FINISHED block on point will be ~11.3" across (the measurement of the FINISHED diagonal).
If you have created a design where you want six on-point blocks/squares that are ~10" across (because you want a 60" wide top), you would reverse the formula:
10" divided by 1.414 = 7.07" (and round up or down),
THEN add the seam allowance to cut the squares.
For blocks, I'd want them to be the 7" (or 7.125" or 7.25", depending on how you round) FINISHED.
10-13-2011, 04:07 AM
#6
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Same subject ... another thread ... might have some extra info for you
http://www.quiltingboard.com/t-159919-1.htm
http://www.quiltingboard.com/t-159919-1.htm
10-13-2011, 07:29 AM
#10
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OK - geometry saves the day again!! If you want the diagonal measurement, use the following formula:
A-squared + B-squared = c-squared
where A and B are the short sides of a triangle and C is the long diagonal side of the triangle.
So, in this case for 6" squares on point, the width would be calculated as: 6x6 + 6x6 = 72. The square root of 72 is 8.48528137. The width could be rounded up to 8.5.
You can get the square root on a calculator that has a square root button. Enter 72, then press the square root button which looks like √ or just google "square root of 72". It will give you the answer.
A-squared + B-squared = c-squared
where A and B are the short sides of a triangle and C is the long diagonal side of the triangle.
So, in this case for 6" squares on point, the width would be calculated as: 6x6 + 6x6 = 72. The square root of 72 is 8.48528137. The width could be rounded up to 8.5.
You can get the square root on a calculator that has a square root button. Enter 72, then press the square root button which looks like √ or just google "square root of 72". It will give you the answer.
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