Binding math ??
#3
Add the measurements of the perimeter of the quilt. 96+96+110+110 = 412. Add another 12 inches for seams, miters, etc. making the number to 424. Divide 424 by 40. This is the approx amount of usable inches in a width-of-fabric. So, 424/40 = 10.6. Round that number up to the nearest whole number. So, you'll need 11 strips at 2.5" wide, making that 26.5" inches of yardage, so approx 3/4 yard. Hope that made sense
Note** - This math is for binding cut along the width-of-fabric, NOT bias and NOT straight-grain**
Note** - This math is for binding cut along the width-of-fabric, NOT bias and NOT straight-grain**
#4
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Join Date: May 2008
Location: MN
Posts: 24,666
(perimeter + 20 inches) multiplied by width of binding -> square inches needed
divided by
(36 inches by WOF) -> square inches in a yard
((96 +96 + 110 + 110 + 20) * 2.5) / (36 * 42)
(432 * 2.5) / 1512
1080 / 1512
0.714
The absolute minimum would be 3/4 of a yard (0.75 yard)
As jeemmerling621 said - this is for binding cut along the width-of-fabric, NOT bias and NOT straight-grain,
I would also go for at least a yard of fabric. If there is some sort of unique design or stripes or something, maybe a bit more.
divided by
(36 inches by WOF) -> square inches in a yard
((96 +96 + 110 + 110 + 20) * 2.5) / (36 * 42)
(432 * 2.5) / 1512
1080 / 1512
0.714
The absolute minimum would be 3/4 of a yard (0.75 yard)
As jeemmerling621 said - this is for binding cut along the width-of-fabric, NOT bias and NOT straight-grain,
I would also go for at least a yard of fabric. If there is some sort of unique design or stripes or something, maybe a bit more.
Last edited by bearisgray; 05-20-2012 at 07:59 PM.
#5
Super Member
Thread Starter
Join Date: Oct 2008
Location: Van. Island, BC
Posts: 1,425
Thank you
Thank you all for this help. That's so helpful as I already had bought 2 yards of fabric for this binding and don't you know I used 3/4 of a yard on something else. So I have 1 1/4 yards left. I so want this UFO done.
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